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Question

2.40 g of the chloroplatinate of a mono acid-base on ignition gave 0.8 g of platinum. Calculate the molecular weight of the base. (Given the atomic weight of Pt=195 g/mol).

A
87.5 g/mol
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B
34.6 g/mol
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C
102.4 g/mol
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D
111.0 g/mol
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Solution

The correct option is A 87.5 g/mol
The formula of the chloroplatinate is (BH)2[PtCl6].
2.40 g of chlorplatinate corresponds to 0.8 g of Platinum.
195 g of platinum will correspond to 2.400.8×195=585 g of chloroplatinate.
The molecular weight of the base is 585409.812=87.5 g/mol.
Here 409.81 is the mass of PtCl6.
Hence, option A is correct.

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