Byju's Answer
Standard VII
Mathematics
Solving Equations with Variable on Both Sides
2x-2+34 x-1=0
Question
2(x − 2) +3(4x − 1) = 0
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Solution
We have:
2
(
x
−
2
)
+
3
(
4
x
−
1
)
=
0
⇒
2
x
−
4
+
12
x
-
3
=0
⇒
14
x
−
7 =0
⇒
14
x
=
7
(By transposition)
⇒
x
=
1
2
CHECK: Substituting
x
=
1
2
in the given equation, we get:
LHS:
2
(
x
−
2
)
+
3
(
4
x
−
1
)
=2
x
−
4
+
12
x
-
3
=2
×
1
2
−
4
+
12
×
1
2
-
3
=1-4+6-3
=
−
7
+
7
=0
RHS: 0
∴ LHS= RHS
Hence,
x
=
1
2
is a solution
of
the
given
equation
.
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