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Question

20 mL of 1 M HCl is titrated against the 1 M NaOH solution. Calculate the pH of the solution when 30 mL NaOH is added?

A
0.7
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B
13.3
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C
12.6
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D
2
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Solution

The correct option is B 13.3
mmol of HCl=20×1=20
mmol of NaOH added=30×1=30

HCl (aq)+NaOH (aq)NaCl (aq)+H2O (l)Initial: 20 30 0 0Final: 0 10 20 20

After titration total HCl will react and excess NaOH is present in the solution.
mmol of NaOH remaing =10
Final concentration=Moles of NaOH remaining Total Volume
Total Volume =30+20=50 mL
[NaOH]final=1050 M=0.2 MpOH=log[OH]pOH=log[0.2]pOH=1log(2)=0.7pH=140.7=13.3

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