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Question

$$20$$ mL of $$x\ M$$ $$HCl$$ neutralizes completely $$10$$ mL of $$0.1\ M$$ $$NaHCO_3$$ solution and a further $$5$$ mL of $$0.2\ M$$ $$Na_2CO_3$$ solution to methyl orange end point. The value of $$x$$ is:


A
0.167 M
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B
0.133 M
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C
0.15 M
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D
0.2 M
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Solution

The correct option is B $$0.15\ M$$
$$20$$ mL of $$x\ M$$ $$HCl=10$$ mL of $$0.1\ M$$ $$NaHCO_3+5$$ mL of $$0.2\ M\ Na_2CO_3$$
(Methyl orange indicated $$100\%$$ reaction of $$NaHCO_3$$ and $$Na_2CO_3$$)
$$0.2\ M$$ $$Na_2CO_3=0.4\ M\ Na_2CO_3$$
$$20\times x-10\times 0.1=5\times 0.1 \times 2\Rightarrow x=0.15$$

Chemistry

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