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Question

# 20 mL solution of 0.1 M ferrous sulphate was completely oxidised using a suitable oxidising agent. What is the number of electrons exchanged?

A
1.204×1022
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B
193
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C
1930
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D
1.204×1021
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Solution

## The correct option is D 1.204×1021During oxidation of FeSO4,Fe2+ ion is oxidises into Fe3+ ion.Fe2+⟶Fe3++e−i.e., 1 e− is transferred from 1 molecule of FeSO4, i.e., from 1 Fe2+ ion.Now, molarity of FeSO4 solution =0.1M and volume of solution =20mL=201000L∴ Number of moles =0.1×201000=0.002∵ In 1 mole FeSO4, number of molecules =6.022×1023∴ In 0.002 mole FeSO4, number of molecules =6.022×1023×0.002=1.204×1021∴ Number of electrons transferred =1.204×1021

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