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Limiting Reagent or Reactant

200 mL mixtur...

Question

$200$ mL mixture of $N a O H$ and $N a_{2} C O_{3}$ was first titrated with phenolpthalein and $17.5$ mL of $H C l$ with normality 0.10 $N$ was required for end point. After this, methyl orange was added and $2.5$ mL of same $H C l$ was again required for next end point. Find out the amounts of $N a O H$ and $N a_{2} C O_{3}$ in the mixture.

A

NaOH= 0.06 g;

N a_{2} C O_{3}

= 0.027 g

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B

NaOH= 0.02 g;

N a_{2} C O_{3}

= 0.035 g

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C

NaOH= 0.027 g;

N a_{2} C O_{3}

= 0.06 g

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D

None of these

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Solution

The correct option is A NaOH= 0.06 g; $N a_{2} C O_{3}$ = 0.027 g
$N a O H + N a_{2} C O_{3}$
$x$ mole $y$ mole
$x + y = \frac{1}{10} \times 17.5 = 1.75$ ....(1)
$y = 0.25$ ..........(2)

$x = 1.5, y = 0.25$ mole
$N a O H = \frac{1.5 \times 40}{1000} g m = 0.06 g m$
$N a_{2} C O_{3} = \frac{0.25 \times 106}{1000} = 0.0265 g m$

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