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Question

200mL of an aqueous solution of a protein contains 1.26g of protein. The osmotic pressure of this solution at 300K is found to be 2.57×103bar . The molar mass of protein will be:
[R = 0.083 L bar mol1K1]

A
51022 g mol1
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B
122044 g mol1
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C
31011 g mol1
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D
61038 g mol1
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Solution

The correct option is D 61038 g mol1
The expression for the osmotic pressure of the solution is given below.

π=CRT

Substitute values in the above expression.

π=wt×1000GMM×V×RT

2.57×103=1.26×1000GMM×200×0.083×300

GMM=61038 g

Thus, the molar mass of protein is 61038 g mol1

Hence, the correct option is D

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