Question

# 200 mL solution of NaOH and Na2CO3 was first titrated with N/10 HCl in presence of HPh 17.5 mL is required to end point. After this MeOH was added and 2.5 mL of same HCl is required. The amount of NaOH in mixture is :

A
0.06 g per 100 mL
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B
0.06 g per 200 mL
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C
0.05 g per 100 mL
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D
0.012 g per 200 mL
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Solution

## The correct option is A 0.06 g per 100 mL200ml mixture of NaOH & Na2CO3​Let NaOH be x moles, Na2CO3​​ be y moles with hph indicatorwe detectx+y moles = 110×17.51000=1.75 millimolesnext with methyl orangey moles =110×2.51000=0.25 millimoles⇒x=1.5 millimoles y=0.25 millimolesweight of NaOH=1.5×40×10−3=60mgHence option A is correct

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