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Question
22.cot x cot 2x-cot 2x cot 3x-cot 3x cot x = 1
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Solution
To prove: cot x cot 2 x − cot 2 x cot 3 x − cot 3 x cot x = 1
cot 3 x = cot ( x + 2 x ) cot 3 x = cot 2 x cot x − 1 cot 2 x + cot x cot 3 x cot 2 x + cot 3 x cot x = cot 2 x cot x − 1 cot x cot 2 x − cot 2 x cot 3 x − cot x cot 3 x = 1
Thus, the given trigonometric equation is proved.
To prove:
Thus, the given trigonometric equation is proved.
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