Question

# 198 is divisible by:

A

11

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B
5
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C
8
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D
6
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Solution

## The correct options are A 11 D 6A number is divisible by 11 if the difference between the sum of digits at its odd places and that of the digits at the even places is divisible by 11. (1 + 8) - 9 = 0 which is divisible by 11. 198 is even number and thus, divisible by 2. The sum of digits 1 + 9 + 8 = 18 which is divisible by 3. So, 198 is also divisible by 3. Since, the number is divisible by both 2 and 3, it is also divisible by 6. A number to be divisible by 5 must end in 0 or 5. Hence, 198 is not divisible by 5. A number is divisible by 8 if the number formed by the last 3 digits of the number are divisible by 8, hence 198 is not divisible by 8.

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