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Crystals of Salts

24.In a flask...

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24.In a flask colourless N2O4 is in equilibrium with brown coloured NO2. At equilibrium when the flask is heated at 100^° , the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy, Δ H for formation of NO2 is

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Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

N O_{2}

. At equilibrium when the flask is heated at

100^{o}

, the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy,

Δ

H for formation of

N O_{2}

Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

{N O}_{2}

. At equilibrium when the flask is heated at

100^{0}

, the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy,

△ H

for the formation of

{N O}_{2}

Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

{N O}_{2}

. At equilibrium when the flask is heated at

100^{o} C

, the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy,

Δ H

for formation of

{N O}_{2}

Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

{N O}_{2}

. At equilibrium, when the flask is heated to

100^{o} C

the brown colour deepens and on cooling, the brown colour became less coloured. The change in enthalpy

Δ H

of the system is:

Q. Assertion :On cooling, the brown colour of

N O_{2}

disappears. Reason: On cooling

N O_{2}

(N_{2} O_{4})

resulting in the pairing of the odd electrons in

N O_{2}

.

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