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Question

25 mL of a mixture of NaOH+Na2CO3, when titrated with N10HCl using phenolphthalein indicator required 25 mL HCl to decolourise phenolphthalein. At this stage, methyl orange was added and the addition of acid was continued. The second endpoint was reached after further addition of 5 mL of the acid. Calculate the amount of Na2CO3 and NaOH in one litre of the solution.

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Solution

Between first and second end points,
NaHCO3+HClNaCl+H2CO3
5 mLN10HCl12Na2CO3 present in 25 mL of a mixture
or 10 mLN10HClNa2CO3 present in 25 mL of a mixture
10 mLN10Na2CO3=0.053 g Na2CO3
Amount of Na2CO3 in one litre of mixture =0.05325×1000
=2.12 g
(255)mLN10HClNaOH present in 25 mL of mixture
25 mLN10NaOH
0.08 g NaOH
Amount of NaOH in one litre of mixture =0.0825×1000
=3.2 g.

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