Question

$25$ raised to the power $\frac{4}{5}$ raised to the power of $3$.

Answer 1

We know that, $(a^m{)}^n=a^{mn}$

Lets evaluate,
$\left\{\right(25{)}^{\frac{4}{5}}{\}}^3$
$=\left\{\right(5^2{)}^{\frac{4}{5}}{\}}^3$

$=(5^{2\times \frac{4}{5}}{)}^3$

$=(5^{\frac{8}{5}}{)}^3$

$=5^{\frac{8}{5}\times 3}$

$=5^{\frac{24}{5}}$