Question

# 250 g of water and equal volume of alcohol of mass 200 g are replaced successively in the same calorimeter and cools from 60∘C to 55∘C in 130 s and 67 s, respectively. If the water equivalent of the calorimeter is 10 g and rate of heat loss is same for both, then the specific heat of alcohol in cal/g∘C is

A
1.3
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B
0.67
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C
0.62
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D
0.985
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Solution

## The correct option is C 0.62Mass of water =250 g Mass of alcohol =200 g Water equivalent of calorimeter, W=10 g Fall of temperature =60−55=5∘C Time taken by water to cool = 130 s TIme taken by alcohol to cool =67 s Heat lost by water and calorimeter =(250+10)5=260×5=1300 cal Rate of loss of heat =1300130=10 cal/s Heat lost by alcohol and calorimeter =(200s+10)5 Rate of loss of heat =(200s+10)567cal/s Rate of loss of heat in the two cases are equal ∴(200s+10)567=10 or s=0.62 cal/g∘C Why this question? Caution: make sure to use specific heat of water in cal/g∘C for the uniformity in units.

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