Question

# 250 g of water at 30oC is contained in a copper vessel of mass 50 g. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to 5oC. Given : specific latent heat of fusion of ice =336×103Jkg−1, specific heat capacity of copper =400Jkg−1K−1, specific heat capacity of water =4200Jkg−1K−1

A
94.93 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
64.93 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
84.93 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
74.93 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is B 74.93 gHeat absorbed by ice is equal to heat absorbed to melt to water at 0oC + Heat absorbed to rise temperature from 0oC to 5oC=m×336×103+m×4200×5Heat released by water and vessel is 0.25×4200×(30−5)+0.05×400×(30−5)Equating above equations, m=74.93×10−3kg=74.93 g

Suggest Corrections
0
Related Videos
The Ideal Gas Equation
CHEMISTRY
Watch in App
Explore more