The correct option is C 4.92 and 3.94
Initial conditions of the solution:
(i) Volume of solution V1 = 250 mL
Molarity of solution M1 = x M
(ii) Volume of solution V2 = 500 mL
Molarity of solution M2 = y M
Final conditions of solution :
Molarity of solution Mf = 1.6 M
Volume of solution Vf = 2 L
⇒x=54 y...(i) .
We know that, in case of dilution, moles remain conserved.
On simplifying ,
From equations (i) and (ii) we get
⇒y=3.94 and x=54 y
Hence, the molarity of the 250 mL solution is 4.92 M and the molarity of the 500 mL solution is 3.94 M