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Quadrilaterals

28. The ortho...

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28. The orthogonal projection( the locus of foot of perpendicular from any point on the line onto the plane) of the given line onto the plane 3x+4y+5z=0 is equal to

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Q. The foot of the perpendicular from the point

(3, 4)

3 x - 4 y + 5 = 0

Q. The foot of the perpendicular from the point of intersection of line

\frac{x - 3}{- 1} = \frac{y - 2}{1} = \frac{z}{5}

x - y + 2 z = 9

3 x + 4 y - z = 0

Q. The co-ordinates of foot of the perpendicular drawn on line

3 x - 4 y - 5 = 0

(0, 5)

Q. Find the coordinates of the foot of perpendicular from the point

(- 1, 3)

3 x - 4 y - 16 = 0

Q. A variable line cuts positive

X - a x i s

Y - a x i s

A

B

respectively such that

3 (O A) + 4 (O B) + O A . O B = 10

then the locus of foot of perpendicular drawn from

(0, 0)

onto this line is

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