29 g of butane is burnt in excess of O2 at STP. Find the volume of the CO2 gas produced at STP.
The correct option is B 44.8 L
The balanced chemical equation is:
No. of moles of C4H10=2958=0.5 mol
Since 1 mol of C4H10 gives 4 mol of CO2.
Hence 0.5 mol of C4H10 will give 41×0.5=2 mol of CO2.
Volume of CO2 produced at STP =22.4 L×2=44.8 L