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Question

29 g of butane is burnt in excess of O2 at STP. Find the volume of the CO2 gas produced at STP.


A
22.4 L
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B
44.8 L
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C
33.6 L
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D
11.2 L
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Solution

The correct option is B 44.8 L
The balanced chemical equation is:
C4H10+138O24CO2+5H2O
No. of moles of C4H10=2958=0.5 mol
Since 1 mol of C4H10 gives 4 mol of CO2.
Hence 0.5 mol of C4H10 will give 41×0.5=2 mol of CO2.

Volume of CO2 produced at STP =22.4 L×2=44.8 L

Chemistry

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