CameraIcon

SearchIcon

MyQuestionIcon

Idea behind a PPC

29.two capaci...

Question

29.two capacitors of capacitances 0.5 mue F and .75 mue F are connected in parallal .a potential difference of 600 v is applied to this combination .what are the charges on the two capacitors ?now the two capacitors are connected in series and the same potential diffrence is applied .find out the charges on the capacitors in this case.

Open in App

Solution

Suggest Corrections

thumbs-up

0

mid-banner-image

mid-banner-image

Similar questions

Q. Two capacitors A and B of capacitance

6 μ F

10 μ F

respectively are connected in parallel and this combination is connected in series with a third capacitors C of

4 μ F

. A potential difference of 100 volt is applied across the entire combination. Find the charge and potential difference across

6 μ F

Q. Assertion :In series combination, charges on two capacitors are always equal. Reason: If charges are same, the total potential difference applied across two capacitors will be distributed in inverse ratio of capacities.

Q. Two capacitors of

3 μ F

6 μ F

are connected in series and a potential difference of

900 V

is applied across the combination. They are then disconnected and reconnected in parallel. The potential difference across the combination is

Q. Two capacitors of capacitance

15 μ F

20 μ F

are connected in series to a

600 V

direct current supply. Charge on each capacitor and potential difference across

15 μ F

capacitor are respectively.

Q. Two capacitors of

1 μ F

2 μ F

are connected in series and this combination is changed upto a potential difference of

120

volt. What will be the potential difference across

1 μ F

View More

Join BYJU'S Learning Program

Select...

similar_icon

Related Videos

lock

Parallel Plate Capacitor

PHYSICS

Watch in App

explore_more_icon

Explore more

Idea behind a PPC

Standard XII Physics

Join BYJU'S Learning Program

Select...