Given (2a3)4÷(4a2)2
=(24a12)÷(42a4) [(ab)n=an×bn] =16a1216a4 [aman=am−n] =a12−4 =a8
(2a3)4÷(4a2)2=
If Ax+By=1 is a normal to the curve ay=x2, then