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Question

2NO+Br22NOBr,

The reaction obeys the following mechanism:

NO+Br2FastNOBr2;

NOBr2+NOSlow−−2NOBr

The rate expression of the above reaction can be written as:

A
r=k[NO]2[Br2]
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B
r=k[NO][Br2]
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C
r=k[NO][Br2]2
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D
r=k[NOBr2]
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Solution

The correct option is C r=k[NO]2[Br2]
For slowest step:
rate=k[NOBr2][NO]....(i)
For equilibrium constant,
Kc=kfkb=[NOBr2][NO][Br2]....(ii)
kf[NO][Br2]=kb[NOBr2]...............(iii)

By eqs. (i) and (iii),
r=k[NO][Br2][NO]
Therefore,
Rate=k[NO]2[Br2].

Hence, option A is correct.

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