Question

$3+23y-8y^2=?\left(a\right)(1-8y)(3+y)\left(b\right)(1+8y)(3-y)\left(c\right)(1-8y)(y-3)\left(d\right)(8y-1)(y+3)$

Answer 1

$3+23y-8y^2=3+24y-y-8y^2\left\{\begin{array}{cc}\because 3\times (-8)=-24& \\ \therefore -24=24\times (-1)& \\ 23=24-1& \end{array}\right\}=3(1+8y)-y(1+8y)=(1+8y)(3-y)$