3, 27, 243, 2187, 19683 … is ___ .

an arithmetic sequence

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a geometric sequence

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(a) and (b) above.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
a geometric sequence

The given sequence is 3, 27, 243, 2187, 19683 …

Let us divide each term of the sequence by its previous term.

$27 \div 3 = 9$

$243 \div 27 = 9$

$2187 \div 243 = 9$

$19683 \div 2187 = 9$

We observe that each term in the sequence is 9 times the previous term.

So the given sequence is a geometric sequence.

If the consecutive terms were formed by adding a constant quantity with the preceding term, the sequence would have been arithmetic.

Suggest Corrections

Similar questions

Is this a geometric sequence?

3, 27, 243, 2187, 19683 …

1)What is volume ?

2) What is magnitude?

3) What is density?

4) What is diffusion?

5)What is osmosis?

p : x

q : x^{2}

x

x^{2}

^{'} \div^{'}

^{'} +^{'}

^{'} \times^{'}

^{'} -^{'}

^{'} -^{'}

^{'} \div^{'}

^{'} +^{'}

^{'} \times^{'}

20 \div 4 \times 12 - 6 + 11

Join BYJU'S Learning Program