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Question

3 grams of carbon is burnt completely in 8 gram of Oxygen and 11 gram of carbon dioxide is produced the mass of carbon dioxide formed when 9 gram of carbon burns in 50 gram of oxygen is


Solution

 

C   +  O2 → CO2

3 g     8 g     11 g

Total mass of reactants = mass of C + mass of O
= 3+8
= 11g

Total mass of reactants = total mass of products

Hence, the law of conservation of mass is proved.

Further, it also shows carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3 : 8.
Thus it also proves the law of constant      proportions.
9 g of carbon must also combine with 8 cross times 3= 24 g of oxygen only.
So carbon dioxide formed when 9 gram of carbon burns in 50 gram of oxygen is 24 + 9 = 33g

Chemistry

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