Question

$3-$Methyl-pent$-2-$ene on reaction with $HBr$ in presence of peroxide forms an addition product.

The number of possible stereoisomers for the products:

• A. $Zero$
• B. $Two$
• C. $Four$
• D. $Six$

Answer 1

Answer: (C)

$Four$

$3-Methyl-pent-2-ene$ on reaction with $HBr$ in presence of $peroxide$ forms an addition product.

A molecule of $HBr$ is added to $C=C$ double bond. The addition follows anti-Markowikoff's rule. $Br$ is added to less substituted C atom.

The number of possible stereoisomers for the products is four. The product has 2 chiral C atoms and is unsymmetrical.

Hence, 4 stereoisomers are possible.