Question

# $$300J$$ of work done in sliding a $$2kg$$ block up an inclined plane of height $$10m$$. Taking $$g=10m/{s}^{2}$$, work done against friction is:

A
200J
B
100J
C
Zero
D
1000J

Solution

## The correct option is B $$100J$$Apply work energy theorem $${ w }_{ external }+{ w }_{ mg }+{ w }_{ friction }=k{ f }_{ z }=0\\ 300-20\times 10+{ w }_{ f }=0\\ { w }_{ f }=100J\\ Work\quad done\quad against\quad friction\quad is\quad 100J$$Physics

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