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Question

$$300J$$ of work done in sliding a $$2kg$$ block up an inclined plane of height $$10m$$. Taking $$g=10m/{s}^{2}$$, work done against friction is:


A
200J
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B
100J
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C
Zero
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D
1000J
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Solution

The correct option is B $$100J$$
Apply work energy theorem 
$${ w }_{ external }+{ w }_{ mg }+{ w }_{ friction }=k{ f }_{ z }=0\\ 300-20\times 10+{ w }_{ f }=0\\ { w }_{ f }=100J\\ Work\quad done\quad against\quad friction\quad is\quad 100J$$


Physics

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