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Crystals of Salts

31. In a flas...

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31. In a flask colourless N2O4 is in equilibrium with brown coloured NO2 .at equilibrium when the flask is heated at 100C the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy,delta H for formation of NO2 is Negative Positive Zero Undefined

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Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

N O_{2}

. At equilibrium when the flask is heated at

100^{o}

, the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy,

Δ

H for formation of

N O_{2}

Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

{N O}_{2}

. At equilibrium when the flask is heated at

100^{o} C

, the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy,

Δ H

for formation of

{N O}_{2}

Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

{N O}_{2}

. At equilibrium when the flask is heated at

100^{0}

, the brown colour deepens and on cooling it becomes less coloured. The change in enthalpy,

△ H

for the formation of

{N O}_{2}

Q. In a flask colourless

N_{2} O_{4}

is in equilibrium with brown coloured

{N O}_{2}

. At equilibrium, when the flask is heated to

100^{o} C

the brown colour deepens and on cooling, the brown colour became less coloured. The change in enthalpy

Δ H

of the system is:

Q. Assertion :On cooling, the brown colour of

N O_{2}

disappears. Reason: On cooling

N O_{2}

(N_{2} O_{4})

resulting in the pairing of the odd electrons in

N O_{2}

.

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