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QUESTION 2.34

Vapour pressure of water at 293K is 17.535 mm Hg. Calculate the vapour pressure of water at 293K when 25g of glucose is dissolved in 450 g of water.


Solution

WB(solute)=25g;MB=180 g mol1;pA=17.535 mm
WA(water)=450g;MA=18g mol;ps=?
pApspA=xB=nBnB+nA
nB=WBMB=25180=0.1389nA=WAMA=45018=2517.535ps17.535=0.13890.1389÷2517.535ps17.535=0.00552ps=17.5350.097ps=17.438 mm Hg


Chemistry
NCERT Textbook
Standard XII

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