35. P is an interior point of triangle ABC. AP,BP,CP when produced meet the sides at D,E,F respectively.If BD=2DC and AE=3EC then (1) AP:PD = (2) BP:PE = (3) CP:PF =

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In triangle ABC, angle B = 35^o, angle C = 65^o and the bisector of angle BAC meets BC in P. Choose the correct descending order of AP, BP and CP

∠ A = 60^{\circ}

∠ C = 40^{\circ}

In triangle ABC; $∠$ A = $60^{0}$ , $∠$ C = $40^{0}$ and bisector of angle ABC meets side AC at point P. Show that BP= CP.

A B C

A B = A C

P

Δ A B C

∠ A B P = ∠ A C P

B P = C P

A P

∠ B A C

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