37. 7log16/15+5log25/24+3log81/80 is equal to 1) log1 2)log2 3)log3 4)log5

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7 l o g (\frac{16}{15}) + 5 l o g (\frac{25}{24}) + 3 l o g (\frac{81}{80})

7 log (\frac{16}{15}) + 5 log (\frac{25}{24}) + 3 log (\frac{81}{80})

7 log (\frac{16}{15}) + 5 log (\frac{25}{24}) + 3 log (\frac{81}{80}) = log 2

7 log \frac{16}{15} + 5 log \frac{25}{24} + 3 log \frac{81}{80} = log 2

7 log (\frac{16}{15}) + 5 log (\frac{25}{24}) + 3 log (\frac{81}{80})

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