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Solving Inequalities

37. If x+1/x=...

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37. If x+1/x=5 then x+1/x is equal to

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x + \frac{1}{x} = 5,

\sqrt{x} + \frac{1}{\sqrt{x}}

\frac{37}{13} = 2 + \frac{1}{x + \frac{1}{y + \frac{1}{z}}}

x, y, z

are positive integer, then

x + y + z

\frac{1}{x - 3} - \frac{1}{x + 5} = \frac{1}{6} (x \neq 3, - 5)

x

$I f x + \frac{1}{x} = 5, t h e n (x^{3} + \frac{1}{x^{3}}) - 5 (x^{2} + \frac{1}{x^{2}}) + (x + \frac{1}{x})$ is equal to

x^{2} - 5 x + 1 = 0

x^{5} + \frac{1}{x^{5}}

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