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Question

3x^2+11x+6=0


Solution

3x²+11x+6

= 3x²+(9+2)x+6

= 3x²+9x+2x+6

= 3x(x+3)+2(x+3)

= (3x+2) (x+3)

3x²+11x+6 = (3x+2) (x+3) = 0

It means (3x+2) = 0 or (x+3) = 0

When (3x+2) = 0 then x = -2/3

when (x+3) = 0 then x = -3 

So x = -3 or x -2/3 will be the solution of this quadratic equation 


 

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