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Question

4.215 g of a metallic carbonate was heated in a hard glass tube and the CO2 evolved was found to measure 1336 ml at 27 and 700 mm pressure. What is the equivalent weight of the metal?


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Solution

Step 1: Given data :

P1=760mmP2=700mm

V1=?V2=1336mLT1=273K,T2=27+273=300k

Step 2: Formula used

P1V1/T1=P2V2/T2 ----------------------1)

Step 3: Calculation of Volume

From 1)

760×V1/273=700×1336/300V1=7×1336×273/3×760=1119.7mL=1.119L

Step 4: Evaluating Weight of Carbon dioxide

Therefore 1.119LCO2=4.215g metallic carbonate

22.4LCO2 is given by 4.215×22.41.119g metallic carbonate

=84.37g

Step 5: Calculating Equivalent weight of metal

Metal carbonate is

MCO3=M+12+48=M+60

Atomic weight of Metal

M=84.3-60=24.3

Equivalent weight of metal =Molecularweight2

=24.37=12.18


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