Question

$4.4g$ of a gas at STP occupies a volume of $2.24L$. The gas can be:

• A. $O_2$
• B. $CO$
• C. $N{O}_2$
• D. $C{O}_2$

Answer 1

Answer: (D)

$C{O}_2$

4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be $C{O}_2$
At STP, 1 mole of any gas occupies a volume of 22.4 L.
4.4 g of a gas at STP occupies a volume of 2.24 L.
Hence, the number of moles of gas $=\frac{2.24}{22.4}=0.1$ moles.
0.1 moles of a gas $=$ 4.4 g.
1 mole of a gas $=4.4\times \frac{1}{0.1}=44$ g.
Thus, the molecular weight of gas is 44 g/mol. It is the molecular weight of $C{O}_2$ gas.