Question

$4.4$ g of an unknown gas occupies $2.24$ litres of volume at STP. The gas may be :

• A. $N_{2}O$
• B. $CO$
• C. $C{O}_2$
• D. $A$ and $C$ both

Answer 1

The correct option is D $A$ and $C$ both

Number of moles = $\frac{2.24}{22.4}=\frac{1}{10}$
or, Number of moles = $\frac{4.4}{Mw}=\frac{1}{10}$
Therefore, Molecular weight = $44$ g.
Gas may be $N_{2}OandC{O}_2$ as they both have molar mass of $44$ g.