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Question

4.4 gm of CO2 and 2.24 litres of H2 at STP (1 atm, 273 K)are mixed in a container. The total number of molecules present in the container will be:

A
6.023×1023
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B
1.2046×1023
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C
6.023×1022
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D
6.023×1024
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Solution

The correct option is B 1.2046×1023
Total number of molecules = No. of molecules of CO2 + No. of molecules of H2.
Let us assume 'n' represent moles and 'N' represent molecules.
nCO2 = 4.444 = 0.1 mol
nH2 = 2.2422.4 = 0.1 mol

NCO2 = nCO2×NA = 0.1×NA molecules
NH2 = nH2×NA = 0.1×NA molecules

Total no of molecules = 0.1×NA + 0.1×NA = 0.2×NA where NA is Avogadro's No. = 6.023×1023
Total no of molecules = 1.2046×1023 molecules

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