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Question

4 g argon (Atomic mass=40) in a bulb is at a temperature of T K has a pressure P atm. When the bulb was placed in hot bath at a temperature 500C more than the first one, 0.8 g of gas had to be removed to get the original pressure. T is equal to :

A
510 k
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B
200 k
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C
100 k
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D
73 k
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Solution

The correct option is D 200 k
PV=nRTP=nRTVSo,440VRT=3.240VR(T+50)40T=32(T+50)40T32T=50×32T=50×328200K
Option B is correct.

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