The correct option is B 672 L CaCO_3+2HCl → CaCl_2 + CO_2 +H_2O ,Mass of limestone = 3000g100g/mol=30 mol 30 #160; moles of limestone wil ...

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Mole Concept

4 kg of 75

Question

$4 k g$ of $75$ % pure limestone is reacted as follows $C a C O_{3} + 2 H C l \to C a C l_{2} + C O_{2} + H_{2} O$ , volume of $C O_{2}$ produced at $S T P$ is:

6.72 L

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672 L

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22.4 L

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448 L

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Solution

The correct option is B $672 L$
$C a C O_{3} + 2 H C l \to C a C l_{2} + C O_{2} + H_{2} O$ ,

Mass of limestone = $\frac{3000 g}{100 g / m o l} = 30 m o l$

$30$ moles of limestone will give $30$ moles of $C O_{2}$

Mass of $C O_{2} = 30 \times 44 g / m o l$

$= 1.324 k g$

Density of $C O_{2} = 1.98 k g / m^{3}$

Volume of $C O_{2} = \frac{1.324}{1.98}$
$= 0.668 m^{3}$ or $668 L$

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