Question

# $$4$$ moles of $$A$$ are mixed with $$4$$ moles of $$B$$ when $$2$$ moles of $$C$$ are formed at equilibrium according to the reaction $$A+B\rightleftharpoons C+D$$.The value of the equilibrium constant is :

A
4
B
1
C
1/2
D
1/4

Solution

## The correct option is B $$1$$$$\underset {4\\4-x}{A}+\underset {4\\4-x}{B}\rightleftharpoons \underset {0\\x}{C} +\underset {0\\x}{D}$$$$\therefore [A]=4-2=2$$       $$[B]=4-2=2$$    $$[C]=2, [D]=2$$The value of the equilibrium constant is, $$K=\dfrac {[C][D]}{[A][B]}=\dfrac {2\times 2}{2\times 2}=1$$The correct option is $$B$$Chemistry

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