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Factorisation by Regrouping Terms

40+3x-x2=? a ...

Question

$40 + 3 x - x^{2} = ? (a) (x + 5) (x - 8) (b) (5 - x) (8 + x) (c) (5 + x) (8 - x) (d) (5 - x) (8 - x)$

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Solution

$40 + 3 x - x^{2} = 40 + 8 x - 5 x - x^{2} {\begin{matrix} ∵ 40 = 8 \times (- 5) 3 = 8 - 5 \end{matrix}} = 8 (5 + x) - x (5 + x) = (5 + x) (8 - x)$

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Similar questions

Q. Tick (✓) the correct answer:
40 + 3x − x² = ?
(a) (x + 5)(x − 8)
(b) (5 − x)(8 + x)
(c) (5 + x)(8 − x)
(d) (5 − x)(8 − x)

Q. The sum of the series

\frac{x}{1 - x^{2}} + \frac{x^{2}}{1 - x^{4}} + \frac{x^{4}}{1 - x^{8}} + . . . . . .

to infinite terms, if |x| > 1 is

\int \frac{x}{\sqrt{8 + x - x^{2}}} d x

(x^{8} y^{7} z^{6} - z^{6} y^{7} x^{8})

y^{7} x^{8} z^{6}

Q. The product (x²−1) (x⁴ + x² + 1) is equal to

(a) x⁸ − 1

(b) x⁸ + 1

(c) x⁶ − 1

(d) x⁶ + 1

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