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Question

40 of a mixture of 0.2 mole of N2 and 0.6 mole of H2 react to give NH3 according to the equation, N2(g)+3H2(g)⇌2NH3(g) at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases are :

A
4:5
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B
5:4
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C
7:10
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D
8:5
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Solution

The correct option is B 4:5
N2+3H22NH3
Initially at equilibrium 0.20.60
(0.2a)(0.63a)2a
Total mixture is 0.8; 40% of it reacts, i.e., 0.8×40100 reacts to give 0.8×40100×12 mole of NH3 or NH3 formed is 0.16 mole or 2a=0.16
a=0.08
Initial mole =0.8
Final mole =(0.20.08)+(0.60.24)+0.16
=0.12+0.36+0.16=0.64
Ratio of final to initial mole =0.640.8=0.8=45

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