$400 c m^{3}$ of a gas at 500 mm pressure is increased to $800 c m^{3}$ . Taking the temperature to remain unchanged, find the decrease in pressure.

550 mm

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450 mm

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250 mm

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350 mm

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Solution

The correct option is C
250 mm

According to Boyle's law: $P_{1} V_{1} = P_{2} V_{2}$

Here $P_{1} = 500 m m : V_{2} = 800 c m^{3} V_{1} = 400 c m^{3}$

$\Rightarrow P_{2} = \frac{500 \times 400}{800}$

$\Rightarrow V_{2} = 250 m m$

Therefore, the volume of gas at STP= 250 mm

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400cm3 of a gas at 500 mm pressure is increased to 800cm3. Taking the temperature to remain unchanged, find the decrease in pressure.

The correct option is C 250 mm According to Boyle's law: P1V1=P2V2 Here P1=500mm : V2=800cm3 V1=400cm3 ⇒P2=500×400800 ⇒V2=250mm Therefore, the volume of gas at STP= 250 mm

$400 c m^{3}$ of a gas at 500 mm pressure is increased to $800 c m^{3}$ . Taking the temperature to remain unchanged, find the decrease in pressure.

The correct option is C
250 mm

According to Boyle's law: $P_{1} V_{1} = P_{2} V_{2}$

Here $P_{1} = 500 m m : V_{2} = 800 c m^{3} V_{1} = 400 c m^{3}$

$\Rightarrow P_{2} = \frac{500 \times 400}{800}$

$\Rightarrow V_{2} = 250 m m$

Therefore, the volume of gas at STP= 250 mm