Question

# Solve, $4\left(2x-1\right)-2\left(x-5\right)=5\left(x+1\right)+3$

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Solution

## Given, $4\left(2x-1\right)-2\left(x-5\right)=5\left(x+1\right)+3$ $⇒\left(8\mathrm{x}-4\right)-\left(2\mathrm{x}-10\right)=5\mathrm{x}+5+3$ $⇒8x-4-2x+10=5x+8$ $⇒6\mathrm{x}-6=5\mathrm{x}+8$ $⇒6\mathrm{x}-5\mathrm{x}=8+6$ $\mathbf{\therefore }\mathbf{x}\mathbf{=}\mathbf{14}$Hence, the required value of $\mathrm{x}=14$.

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