Question

# 4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be:

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Solution

## Step 1: Given data At STP, a mole of any gas occupies a volume of $22.4L$ $4.4g$ of a gas at STP occupies a volume of$2.24L$Step 2: Calculating the number of moles of gas Hence, the number of moles of gas,$=\frac{2.24}{22.4}\phantom{\rule{0ex}{0ex}}=0.1moles.$ Step 3: Evaluating molecular weight $0.1$moles of a gas =$4.4g.$A mole of a gas$=4.4×\frac{1}{0.1}\phantom{\rule{0ex}{0ex}}=44g$This is equal to the molecular weight of carbon dioxide , $=12+2×16\left(C{O}_{2}\right)\phantom{\rule{0ex}{0ex}}=44g$ Thus, the molecular weight of gas is$44g/mol$. It is the molecular weight of ${\mathrm{CO}}_{2}$(Carbon dioxide) gas.

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