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Depression in Freezing Point

45g of ethyle...

Question

$45$ g of ethylene glycol $(C_{2} H_{6} O_{2})$ is mixed with $600$ g of water. The freezing point of the solution is ( $K_{f}$ for water is $1.86$ K kg $m o l^{- 1}$ ).

273.95

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270.75

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370.95

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373.95

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Solution

The correct option is C $270.75$ K
We have,
$Δ T_{f} = i \times K_{f} \times m$

$273 - T_{S} = 1.86 \times \frac{45}{62 \times 600} \times 1000$

So, freezing point of solution = $270.75 K$

Option B is correct.

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Similar questions

45 g

600 g

k_{f} = 1.86 K k g m o l^{- 1}

c m^{3}

- 34^{\circ}

K_{f}

m o l^{- 1}

Calculate the freezing point of a solution when 31 gram of Ethylene glycol is dissolved in 500 gram of water. (

Kf for water=1.86 k kg /mol

31 g

(C_{2} H_{6} O_{2})

500 g

K_{f}

2 K

k g

{m o l}^{- 1}

K

= 273 K

50 c m^{3}

- 4^{o} C

(K_{f}

= 1.86 K k g m o l^{- 1}

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