Solve: $\frac{4}{7} + 3 \frac{3}{4}$

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Solution

$\frac{4}{7} + 3 \frac{3}{4}$
$= \frac{4}{7} + \frac{15}{4}$
LCM of $7$ and $4$ is $28$
$= \frac{4 \times 3 + 15 \times 7}{28}$
$= \frac{12 + 105}{28}$
$= \frac{117}{28}$
$= 4 \frac{5}{28}$

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