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Question

47C4+5r=152rC3

 



A

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B

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C

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D

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Solution

The correct option is C


47C4+5r=152rC3 = 51C3+50C3+49C3+48C3+47C3+47C4

 =51C3+50C3+49C3+48C3+48C4

 =51C3+50C3+49C3+49C4

=51C3+50C3+50C4+51C3+51C4 = 52C4


Mathematics

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