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Question

47C4 +5r=1 .52rC3is equal to :

A
51C4
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B
52C4
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C
53C4
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D
None of these
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Solution

The correct option is B 52C4
=47C4+521C3+522C3+523C3+524C3+525C3
=47C4+51C3+50C3+49C3+4C3+47C3
=(47C4+47C3)+4C3+49C3+50C3+51C3
=(48C4+48C3+49C3+50C3+51C3
(nCr+nCr1=n+1Cr)
=(49C4+49C3)+50C3+51C3)(nCr+nCr1=n+1Cr)
=(50C4+50C3)+51C3)(nCr+nCr1=n+1Cr)
=(51C4+51C3(nCr+nCr1=n+1Cr)
=52C4(nCr+nCr1=n+1Cr)

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