$(4 x^{2} + 4 x - 3)$ =?

(a) $(2 x - 1) (2 x - 3)$

(b) $(2 x + 1) (2 x - 3)$

(c) $(2 x + 3) (2 x - 1)$

(d) None of these

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Solution

(c) $(2 x + 3) (2 x - 1)$

$4 x^{2} + 4 x - 3 = 4 x^{2} + 6 x - 2 x - 3 = 2 x^{2} (x + 3) - 12 (x + 3) = (2 x + 3) (2 x - 1)$

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