$(4 x^{2} + x y + y^{2}) \div (x y)$ = ______

\frac{x}{y} + 1 + \frac{y^{2}}{x}

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\frac{4 x}{y} + 1 + \frac{y}{x}

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\frac{4 x}{y} + \frac{2}{y} + \frac{1}{x y}

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\frac{4 x^{2}}{y} + x + \frac{y}{x}

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Solution

The correct option is B $\frac{4 x}{y} + 1 + \frac{y}{x}$
Here, we need to divide a polynomial by a monomial.
So let us divide each term of the polynomial by the monomial.
$\frac{4 x^{2} + x y + y^{2}}{x y}$ = $\frac{4 x^{2}}{x y} + \frac{x y}{x y} + \frac{y^{2}}{x y}$
= $\frac{4 x}{y} + 1 + \frac{y}{x}$

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Similar questions

If 4x² + y² = 40 and xy = 6, find 2x + y.

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